Raising Your Deductible: The Claim Frequency That Decides It
2026-09-18
Short answer: Divide the increase in deductible by the annual premium saving. That gives the claim frequency at which the two options break even. Raising a deductible by $500 to save $240 a year breaks even at one claim every 2.08 years — so if you claim less often than that, the higher deductible wins, provided you can produce the deductible in cash on the day.
The question this answers
Every insurance quote offers a menu: pay less each year and carry more of the first loss yourself, or pay more each year and carry less. The marketing on both sides is useless. There is one number that decides it.
The arithmetic
break-even interval (years) = (higher deductible − lower deductible) ÷ annual premium savingWorked example — an auto policy quoted at two deductibles:
| Option | Deductible | Annual premium |
|---|---|---|
| A | $500 | $1,640 |
| B | $1,000 | $1,400 |
| Difference | $500 more exposure | $240 saved per year |
$500 ÷ $240 = 2.08 yearsOption B wins whenever you claim less often than once every 2.08 years. Over ten years, someone who claims twice pays 2,400 less in premiums and 1,000 more in deductibles: 1,400 ahead. Someone who claims six times pays 2,400 less in premiums and 3,000 more in deductibles: 600 behind.
Reading the result
The break-even interval is short. Two years between claims is a high claim rate for most households — many people go a decade without one. That is why, on most policies, the higher deductible is the better expected-value choice, and it is why insurers offer the saving in the first place.
The arithmetic is also insensitive to the size of the loss, which surprises people. A 1,000 deductible costs 500 more than a 500 deductible on a 2,000 claim and on a $60,000 claim alike. The catastrophic case, the one insurance exists for, is not where the deductible choice matters.
The condition that overrides the arithmetic
You must be able to produce the deductible in cash on the day of the loss. A car that is undriveable until you find 1,000 is a bigger problem than 240 a year is a solution. If the higher deductible would go on a credit card at 24% APR, the $240 saving is spent on interest within a year and the arithmetic reverses.
The practical order is: build the deductible in cash first, then raise the deductible to that level, then bank the premium saving.
The second effect, which is usually the larger one
A higher deductible stops you filing small claims. That matters more than the premium saving, because small claims are frequently a net loss once the surcharge that follows them is counted — a $900 claim that triggers three years of higher premiums can cost more than it paid.
A $1,000 deductible makes that decision for you. It is a commitment device as much as a price.
What would reverse the conclusion
- A claim record above the break-even frequency. Two or more claims in the last four years is real evidence, and it points the other way.
- A deductible you cannot cover. Then the premium is buying liquidity, not just cover, and liquidity is worth paying for.
- A per-claim rather than per-year deductible. Where each claim carries its own deductible, a bad year with two losses costs two deductibles. Check which structure the policy uses before assuming the interval.
- Policy differences beyond the deductible. If the cheaper quote also carries lower limits or new exclusions, you are not comparing deductibles any more, and this arithmetic does not apply.
Run your own numbers in the budget builder →